Up Learn – A Level physics (AQA) – THERMAL PHYSICS
Specific Heat Capacity Practical: Thermal Equilibrium
Using specific heat capacity to find the final temperature of a mixture.
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Thermal Physics
2. Thermal Equilibrium (free trial)
3. Heating and Kinetic Energy (free trial)
4. What is Temperature? (free trial)
5. Defining Temperature (free trial)
6. Temperature Scales (free trial)
7. The Kelvin Scale(free trial)
8. Degrees Celsius to Kelvin (free trial)
2. States of Matter (free trial)
3. Intermolecular Forces (free trial)
4. Forces or Bonds? – Article (free trial)
5. What is Internal Energy? (free trial)
6. Thermal Energy and Internal Energy – Article (free trial)
7. Change in Internal Energy – Energy Transfer by Heating (Part 1) (free trial)
8. Change in Internal Energy – Energy Transfer by Heating (Part 2) (free trial)
9. Change in Internal Energy – Energy Transfer by Work (free trial)
10. Change in Internal Energy – Heating and Work (free trial)
11. ΔU = Q + W – Article (free trial)
12. Constant Internal Energy (free trial)
2. Factors Affecting Temperature Increase – Mass and Energy (free trial)
3. Factors Affecting Temperature Increase – Specific Heat Capacity (free trial)
4. Calculating Energy Required to Increase Temperature (free trial)
5. Objects in Thermal Equilibrium (free trial)
6. Worked Example – Calculating Temperature at Thermal Equilibrium (free trial)
7. Assumption of Energy Transfer (free trial)
8. Calculating c Using Gravitational Potential Energy (free trial)
9. Calculating c for a Solid using Electrical Energy (free trial)
10. Calculating c for a Liquid using Electrical Energy (free trial)
11. Calculating c Using Continuous Flow 1 (free trial)
12. Calculating c Using Continuous Flow 2 (free trial)
Here we have a glass cup
It has a mass of 0.200 kilograms, this specific heat capacity, and a temperature of 20 degrees Celsius
If we pour in 0.100 kg of water, which has this specific heat capacity and temperature…
What is the temperature of the water and glass once they’re in thermal equilibrium?
Now, we know that during heating, energy is transferred from an object at a higher temperature to an object at a lower temperature
So, the glass transfers energy, and the water gains it
And we assume that all the energy transferred from the glass is gained by the water.
Next, we know that we can use this formula to calculate Q
So, we can substitute for Q using this
And now, we can begin to substitute in our values, starting with our values for water.
So, we substitute the value for the mass of water here…
We substitute the value for the specific heat capacity here…
And we know that the change in temperature is equal to the final temperature subtract the initial temperature
So, we can add our initial temperature here
And expanding the brackets, we calculate this to be equal to…
Expanding the brackets, we calculate this.
Next, we do the same with our values for the glass.
So, we substitute in our values here…
And this time, when we expand the brackets, we calculate this to be equal to…
Expanding the brackets, we calculate this
So, now we can calculate the final temperature, which is.
First, we collect like terms
Then, we divide by 588 to make the final temperature the subject…
And we calculate that the final temperature is 9.29 degrees Celsius.
So, this is the temperature of the water and glass in thermal equilibrium!